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ANSWERS - HURDLE 10 : AVERAGES

Ans1. Option 5

Ans2. Option 4

Ans3. 25

Ans4. 25

Ans5. 35

Hurdle 10 : Averages
Q1 . There are 22 numbers with biggest number being 100 and the smallest being 0.
Hurdle10.htm

  Links of Hurdle 1 to 30
Our Hurdles are prepared on the basis of past entrance tests  papers.

Hurdle.htm
  Links of Hurdle 31 to 78
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Hurdle31onwards.htm

Ans6. 44

Ans7. 63

Ans 8. 31 ,

Ans 9. 127 ,

Ans10. 13 and 17 ,

Ans11. 5 and 6 ,

Ans12. 22 ,

Ans13. 13,17 and 19,

Ans14. 33,33,33 ,

Ans15. 5,7,11 ,

Ans16. 25,25 and 35 ,

Ans17. 37,40,42 ,

Ans18. 30 ,

Ans19. B , Ans20. D , Ans21. F , Ans22. J , Ans23. K , Ans24. M , Ans25. N

Ans26. Option A. Both the statement are false

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HERE ARE SOLUTIONS OF SOME OF THE QUESTIONS, THE REST MAY BE SOLVED USING THE SAME METHOD.

Ans 1 : The correct answer is option 5 . Check the following examples.
1) 8 numbers are 44 and 12 numbers are 54
2) 8 numbers are 44 and 12 numbers are 54
3) 8 numbers are 56 and 12 numbers are 46
4) 8 numbers are 56 and 12 numbers are 46


Ans 2 : Option 4 is the correct answer.
Minimum Avg= (11*50-100)/10 = 45
Maximum Avg= (11*50-1)/10 =54.9

Ans 3 : 17*17 – X = 16.5*16 =>X= 25

Ans 4. Avg. of 37 employees is 27 , so sum = 37*27=999
As one employees goes and one comes in, the total employee remain same.
New Avg = 25 , so new sum = 37*25= 925
Difference between the Two sums = 999-925= 74
The person who left had a salary of 99. (UrPercentile.com)
So the person who joined will have 99-74= 25.

Ans 10. (16*22-x)/14=23 , x=30
thus 2 consecutive prime nos are 13,17.
Hint : As the prime numbers are consecutive, they are likely to be near and around 30/2 = 15. (UrPercentile.com)

Ans 13. Avg of 22 numbers is 29. So sum = 22*29= 638.
After removing 3 numbers the avg. becomes 31.
So new sum = (22-3)*31= 589
Difference= 49.
The three consecutive prime numbers can only be 13,17,19.
Hint : As the prime numbers are consecutive, they are likely to be near and around 49/3 = 16.33. (UrPercentile.com)

Ans 17 . Sum = 28*19=532
new sum = 31*21= 651
Difference = 119.
So A+B+C=119 ---(i)
as B-A=3 or B=A+3 ---(ii)
C-A=5 or C= A+5 ----- (iii)
put value of (ii) and (iii) in (i)
A+(A+3)+(A+5)= 119
so A=37
put value of A in (ii) and (iii) to get value of B and C
B= 50 and C=42

Ans 26 : Both statement are false.
Read :
"In the case of our solar system, this led to eight major bodies. The ninth planet, Pluto, is believed to be a survivor of an early
subclass of bodies in the solar system called icy dwarfs." And "But the discovery of many `hot Jupiters' (circling close to the
parent star) as well as frequently non-circular orbits is at variance with the expected picture."

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