ANSWERS - HURDLE 21: RATION

Ans1. 1 : 3 boy = 1 men.
30 boy = 10 men.
Initial number of men 130+10 = 140
Let each men consume Y amount each day .
So total ration = 140* 26* Y
New number of men = 160
Let new boys be 3X
New number of men = 160 +X
Each will consume Y amount each day .
So (160 +X)Y*20 = 140*26*Y
160*20 + 20 X = 140*26
20X = 3640 - 3200
so 20X = 440
X = 22
So 3X = 66
So new number of boys = 66.

Ans2. As 1 man = 2 boys, and 15 men are added and 30 boys are reduced or 15*2-30= 0 boys are added so the ration will last for same number of days that is 32.

Ans3.As 1 man = 2 boys,
125 men=125*2 boy = 250 boys
So total boys initially = 250+46= 296 boys
Let each boy consume x quantity each day, so the quantity in stock = 296*43*X
Now 36 men are added and 24 boys are reduced or 36*2-24= 48 boys are added
so new number of boys = 296+48 = 344 who will consume 244X quantity each day.
so the number of days the stock will last = 296*43*X/ 344X = 37 days.

Ans4. 4 boy = 1 man.
Initial number of man = 128 + 128/4 = 160
Let each consume Y quantity on each day .
Total ration = 160*35*Y
Let New boys = 4X
New number of Men = 128 +58 +4X/4 = 186 +X
Each consume Y quantity on each day .
The ration lasts for 35 – 10 = 25 days
So (186 +X)Y 25 = 160* 35*Y
186*25 + 25X = 160*35
25X = 950
X = 38
4X = 152
So the number of increase in boy was 152-128 = 24

Ans5. 3 boys = 1 men
Initial number of men = 225 + 135/3 = 270
Let each men consume Y quantity.
Total Ration = 270*100*Y
Let the reduction in number of men and boy be by X each.
Effective reduction = X +X/3 men = 4X/3
So new number of men = (270-4X/3)
Each consume Y quantity
(270-4X/3)*Y *108 = 27000*Y
270*108 – 108*4X/3 = 27000
144X = 2160
X = 2160/144 = 15
New Number of boy = 135 –15 = 120

Ans6. 81

Ans7. 58

Ans8. 90

Ans9. 135

Ans10. 216

Ans11. 76

Ans12. 24

Ans13. 34

Ans14. 29

Ans15. 30

Ans16. C , Ans17. E , Ans18. B , Ans19. H , Ans20. A